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Question

Which pair of functions is identical?

A
sin1(sinx) and sin(sin1x)
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B
logeex,loglogex
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C
logex2,2logex
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D
none of these
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Solution

The correct option is C none of these
Here, (a)sin1(sinx) is defined for x[π2,π2], while sin(sin1x) is defined only for x[1,1]
(b) logeex is defined for all x, while elogex is defined for x>0.
(c) logex2 is defined for all xϵR{0}, while 2logx is defined for x>0
None of identical.
Hence, (d) is the correct answer.

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