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Which pair of...

Question

Which pair of quantum numbers determine the energy of an electron in an orbital?

A

n and l

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B

n and m

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C

n and m_s

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D

l and m

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Solution

The correct option is A
n and l

The sum of value of Principal quantum number (n) and Azimuthal quantum number (l) determines the energy of an electron in an orbital.

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Similar questions

Q. Assertion :In hydrogen and hydrogen like species, orbital energy depends only on the quantum number n whereas in multi-electron atom it depends on quantum numbers n and l. Reason: The principal quantum number determines the size and the energy of the orbital.

Q. (a) An electron is in

5 f

-orbital. What possible values of quantum numbers

n, l, m

s

can it have?
(b) What designation is given to an orbital having
(i)

n = 2, l = 1

n = 3, l = 0

Q. An electron in an atom has the following set of four quantum numbers to which orbital it belong to:

$n$	$l$	$m_{l}$	$m_{s}$
2	0	0	$+ \frac{1}{2}$

Q. In a multi-electron atom, which of the following orbitals described by the three quantum numbers will have the same energy in the absence of magnetic and electric fields?
(A)

n = 1, l = 0, m = 0

n = 2, l = 0, m = 0

n = 2, l = 1, m = 1

n = 3, l = 2, m = 1

n = 3, l = 2, m = 0

Q. Which of the following sets of quantum number for orbitals in hydrogen atom has a greater energy of electrons?
a. n =3, l=2 and m = +1

b. n= 3, l=2 and m= -1

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