Which pair of species has the same percentage of carbon?

[1 mark]

C H_{3} C O O H a n d C_{2} H_{5} O H

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C H_{3} C O O H a n d C_{6} H_{12} O_{6}

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C_{6} H_{12} O_{6} a n d C_{12} H_{22} O_{11}

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H C O O C H_{3} a n d C_{12} H_{22} O_{11}

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Solution

The correct option is B $C H_{3} C O O H a n d C_{6} H_{12} O_{6}$
${C H}_{3} C O O H$ and $C_{6} H_{12} O_{6}$ pairs of species have the same percentage of carbon.

Species $Weight of Carbon = No . of carbon \times 12$ Molecular mass of compound $% of Carbon$

${C H}_{3} C O O H$ 2 × 12 = 24 60 $\frac{24}{60} \times 100 = 40 %$

$C_{2} H_{5} O H$ 2 × 12 = 24 46 $\frac{24}{46} \times 100 = 52 %$

$C_{6} H_{12} O_{6}$ 6 × 12 = 72 180 $\frac{72}{180} \times 100 = 40 %$

$C_{12} H_{22} O_{11}$ 12 × 12 = 144 342 $\frac{144}{342} \times 100 = 42 %$

Suggest Corrections

Species	$Weight of Carbon = No . of carbon \times 12$	Molecular mass of compound	$% of Carbon$
${C H}_{3} C O O H$	2 × 12 = 24	60	$\frac{24}{60} \times 100 = 40 %$
$C_{2} H_{5} O H$	2 × 12 = 24	46	$\frac{24}{46} \times 100 = 52 %$
$C_{6} H_{12} O_{6}$	6 × 12 = 72	180	$\frac{72}{180} \times 100 = 40 %$
$C_{12} H_{22} O_{11}$	12 × 12 = 144	342	$\frac{144}{342} \times 100 = 42 %$