1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VII
Mathematics
Properties of Division of Integers
Which part of...
Question
Which part of the following equation is incorrect?
1440
÷
36
=
45
A
Dividend
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Divisor
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Quotient
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
All parts are correct.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
Quotient
The number
1440
can be written as
1000
+
400
+
40
.
So, calculating
1440
÷
36
using the box method, we get the following:
Adding the patial quotients together, we get,
20
+
10
+
10
=
40
.
So, the final quotient of
1440
÷
36
is
40
.
Hence,
1440
÷
36
=
40
.
Comparing this to
1440
÷
36
=
45
, we find that the incorrect value is
45
.
But, the general form a division equation is
D
i
v
i
d
e
n
d
÷
D
i
v
i
s
o
r
=
Q
u
o
t
i
e
n
t
.
So, comparing
1440
÷
36
=
45
to
D
i
v
i
d
e
n
d
÷
D
i
v
i
s
o
r
=
Q
u
o
t
i
e
n
t
, we find that the incorrect part of the equation is the
q
u
o
t
i
e
n
t
.
Suggest Corrections
0
Similar questions
Q.
Which of the following equation is incorrect?
Q.
Which of the following is incorrect about the following reaction –
2
S
O
2
(
g
)
+
O
2
(
g
)
⇋
2
S
O
3
(
g
)
△
H
=
−
45
k
C
a
l
Q.
RHS part of the equation
36
(
8
+
3
)
=
_______
Q.
What is the R.H.S. part of the equation 36(8 - 3) = ?
Q.
What is the R.H.S. part of the equation 36(8 - 3) = ?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Properties of Division of Integers
MATHEMATICS
Watch in App
Explore more
Properties of Division of Integers
Standard VII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app