Question

Which pigment system ultimately donates $e^{-}$ for the reduction of NADP?

• A. PS- II
• B. PS- I
• C. $C{O}_2$
• D. Plastoquinone

Answer 1

The correct option is B PS- I

During non-cyclic electron flow, the electron ejected on behalf of PS I by the reaction centre P${}_7$${}_0$${}_0$ moves uphill and reduces an iron-sulphur protein. From here, it moves downhill to ferredoxin (Fd) and then to $NAD{P}^{+}$, which is reduced to $NADP{H}_2$. The enzyme which actually forms reduced $NADP{H}_2$ is ferredoxin NADPH oxidoreductase.

so, the correct answer is option B.