Which reaction cannot give anhydrous $A l C l_{3}$ ?

Heating of

A l C l_{3} \cdot 6 H_{2} O

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Passing dry HCl over heated aluminium powder.

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Passing dry

C l_{2}

over heated aluminium powder.

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Heating a mixture of alumina and coke in a current of dry

C l_{2}

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Solution

The correct option is A Heating of $A l C l_{3} \cdot 6 H_{2} O$
Heating of $A l C l_{3} \cdot 6 H_{2} O$ ( $A l C l_{3}$ is covalent and hence when the water of crystallisation is evaporated, the $A l C l_{3}$ will react with the water to form the hydroxide)
Passing dry HCl over heated aluminium powder. $2 A l + 6 H C l \to 2 A l C l_{3} + 3 H_{2}$
Passing dry $C l_{2}$ over heated aluminium powder.( $A l C l_{3}$ is covalent and hence when the water of crystallisation is evaporated, the $A l C l_{3}$ will react with the water to form the hydroxide)
Heating a mixture of alumina and coke in a current of dry $C l_{2}$ .( $A l_{2} O_{3} + 3 C + 3 C l_{2} \to 2 A l C l_{3} + 3 C O$ )
So option B,C D produces aluminium chloride.
Hence option A is correct.

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