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Introduction

Which reactio...

Question

Which reaction is not feasible ?

A

2 K I + B r_{2} ⟶ 2 K B r + I_{2}

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B

2 K B r + I_{2} ⟶ 2 K I + B r_{2}

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C

2 K B r + C l_{2} ⟶ 2 K C l + B r_{2}

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D

2 H_{2} O + 2 F_{2} ⟶ 4 H F + O_{2}

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Solution

The correct option is B $2 K B r + I_{2} ⟶ 2 K I + B r_{2}$
$2 K B r + I_{2} ⟶ 2 K I + B r_{2}$
This reaction is not possible because $B r^{-}$ ion can't be oxidized to $B r_{2}$ with $I_{2}$ as $I_{2}$ can't oxidize bromine since $B r_{2}$ is a better oxidizing agent than iodine.

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Similar questions

Q. Match the following

	Column-1		Column-2
A	Acidic reactions	p	${C l}_{2} + 2 K B r \to 2 K C l + {B r}_{2}$
B	Displacement reactions	q	$C a + {C l}_{2} \to {C a C l}_{2}$
C	Oxidising properties	r	${C l}_{2} + H_{2} O \to H O C l + H C l$
D	Addition reactions	s	$2 K I \to {C l}_{2} + 2 K C l + I_{2}$
E	Reaction with metals	t	${S O}_{2} + {C l}_{2} \to {S O}_{2} {C l}_{2}$

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

Q. Which reaction is this?

2 K I + C l_{2} \to 2 K C l + I_{2}

Q. Consider the following orders –
(1)

F_{2} > C l_{2} > B r_{2} > I_{2} :

boiling point
(2)

F_{2} > C l_{2} > B r_{2} > I_{2} :

oxidizing nature
(3)

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Acidic nature
(8)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Oxidizing nature
Then calculate

(x^{2} + y^{2})

x

is correct order and

y

is incorrect order.

Q. Consider the reaction:

C l_{2} + 2 K I \to I_{2} + 2 K C l

Which species will be reduced at the cathode?

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