Which reaction obeys the Markownikoff rule?

(C H_{3})_{2} C H - C H = C H - C H_{3} + H B r \to (C H_{3})_{3} C - C B r H - C H_{3}

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(C H_{3})_{3} C - C H = C H_{2} + H B r \to (C H_{3})_{3} C - C B r H - C H_{3}

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(C H_{3})_{3} C - C H = C H - C (C H_{3})_{3} + H B r \to (C H_{3})_{3} C - C B r H - C H_{2} - C (C H 3) 3

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(C H_{3})_{3} C - C H = C H_{2} + H B r \to (C H_{3})_{3} C - C H_{2} - C H_{2} - B r

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Solution

The correct option is B $(C H_{3})_{3} C - C H = C H_{2} + H B r \to (C H_{3})_{3} C - C B r H - C H_{3}$
Markovnikov's rule can be stated that the addition of a HX to an unsymmetrical alkene, hydrogen atom is added to the carbon with the greater number of hydrogen atoms while the Br is added to the carbon with the fewer number of hydrogen atoms.

Exactly the opposite of Markovniko's rule is Anti-Markovnikov's rule

All the above reactions are following anti-Markovnikov's rule except the second equation.

${(C H_{3})}_{3} C - C H = C H_{2} + H B r ⟶ {(C H_{3})}_{3} C - C B r H - C H_{3}$

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Similar questions

Predict the products of the following reactions:

(i)

(ii)

(iii)

(iv)

{{(C H}_{3})}_{3} C - C H = C H_{2}

C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3} + H B r \to

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

(C H_{3})_{3} C - C H = C H_{2}

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