Which reaction product is formed from benzaldehyde

C_{6} H_{5} N H_{2}

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C_{6} H_{5} C H = N C H_{3}

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C_{6} H_{5} C H_{2} N H_{2}

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C_{6} H_{5} C O N H_{2}

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Solution

The correct option is B $C_{6} H_{5} C H = N C H_{3}$
$C_{6} H_{5} C H = N C H_{3}$ on oxidation will give benzaldehyde

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Similar questions

C_{6} H_{5} C H O N H_{2} O H / H^{+} - ------- \to △ (X) P_{2} O_{5} - -- \to △ (Y) H_{2} O / H^{+} - ---- \to (Z)

X

Y

Z

Arrange the following in increasing order of their basic strength:

(i) C₂H₅NH₂, C₆H₅NH₂, NH₃, C₆H₅CH₂NH₂ and (C₂H₅)₂NH

(ii) C₂H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N, C₆H₅NH₂

(iii) CH₃NH₂, (CH₃)₂NH, (CH₃)₃N, C₆H₅NH₂, C₆H₅CH₂NH₂.

(C_{6} H_{5} C H = O)

[(C H_{3})_{2} C + O]

C_{6} H_{5} N H_{2}, C_{6} H_{5} N H C H_{3}, C_{6} H_{5} C H_{2} N H_{2}

C_{2} H_{5} N H_{2}, C_{6} H_{5} N H_{2}, N H_{3}, C_{6} H_{5} C H_{2} N H_{2}

(C_{2} H_{5})_{2} N H

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