Which reaction represents an oxidation-reduction reaction?

3 O_{2} (g) ⇌ 2 O_{3} (g)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O H^{-} + H_{3} O^{-} ⇌ 2 H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B a C l_{2} .2 H_{2} O (s) △ \to B a C l_{2} (s) + 2 H_{2} O (g)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C a^{2 +} + C O_{3}^{2 -} \to C a C O_{3} (s)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e + C u^{2 +} ⇌ F e^{2 +} + C u

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E $F e + C u^{2 +} ⇌ F e^{2 +} + C u$
An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species.
$F e + {C u}^{2 +} ⇌ {F e}^{2 +} + C u$
In the above reaction, $F e$ is oxidised by gaining $2$ electrons while $C u$ is reduced by loosing $2$ electrons.
Hence the above reaction is represents an oxidation-reduction reaction.
Hence the required answer is $(E) F e + {C u}^{2 +} ⇌ {F e}^{2 +} + C u$ .

Suggest Corrections

Similar questions

C u \to C u^{2 +} + 2 e^{-}

F e^{2 +} + 2 e^{-} \to F e

E^{\circ} = - 0.44 V

C u^{2 +} + 2 e^{-} \to C u

E^{\circ} = + 0.34 V

E^{\circ}

F e + C u^{2 +} ⇋ F e^{2} + C u

Δ G^{o}

C u^{2 +} + F e \to F e^{2 +} + C u

E_{C u^{2 +} | C u}^{o} = + 0.34

E_{F e^{2 +} | F e}^{o} = - 0.44

25^{\circ} C

2 H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}

- 0.8277 v o l t

2 H_{2} O ⇌ H_{3} O^{+} + O H^{-}

25^{\circ} C

The oxidation and reduction half reactions of the reaction

2Al_(s) + 3Cu²⁺_(aq) → 2Al³⁺_(aq) + 3Cu_(s) are

Join BYJU'S Learning Program