Which reaction represents the oxidising behaviour of $H_{2} S O_{4}$ ?

N a C l + H_{2} S O_{4} ⟶ N a H S O_{4} + H C l

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2 N a O H + H_{2} S O_{4} ⟶ {N a}_{2} S O_{4} + 2 H_{2} O

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2 H I + H_{2} S O_{4} ⟶ I_{2} + S O_{2} + 2 H_{2} O

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2 P {C l}_{5} + H_{2} S O_{4} ⟶ 2 P O {C l}_{3} + S O_{2} {C l}_{2} + 2 H C l

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Solution

The correct option is C $2 H I + H_{2} S O_{4} ⟶ I_{2} + S O_{2} + 2 H_{2} O$
The reaction $2 H I + H_{2} S O_{4} ⟶ I_{2} + S O_{2} + 2 H_{2} O$ represents the oxidising behaviour of $H_{2} S O_{4}$
The oxidation number of iodine increases from $- 1$ (in $H I$ ) to $0$ in $I_{2}$ . Thus, iodine is oxidised.
For other reactions, there is no change in the oxidation number.

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H_{2} S O_{4}

Which of the following chemical reaction depicts the oxidizing behavior of $H_{2} S O_{4}$ ?

H C l + N a O H \to N a C l + H_{2} O + x c a l .

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O + y c a l

2 N a O H + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H_{2} O

H C l + N a O H \to N a C l + H_{2} O + x c a l

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O + y c a l

x

y

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