Which reagent does not give oxygen as one of the product during oxidation with ozone?

S O_{2}

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S n C l_{2} / H C l

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H_{2} S

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P b S

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Solution

The correct option is B $S n C l_{2} / H C l$
$S n C l_{2} / H C l$ is a reducing agent. It gives $S n C l_{4}$ on reaction with ozone. The other reactants gives ozone as follows.
$S O_{2} + O_{3} \to O_{2}$
$S n C l_{2} + H C l + O_{3} \to S n C l_{4} + H_{2} O$
$H_{2} S + O_{3} \to H_{2} O + S O_{2} + O_{2}$
$P b S + O_{3} \to P b S O_{4} + O_{2}$

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