Which reagent is the most useful for distinguishing compound I from the rest of the compounds?
$C H_{3} - C H_{2} C \equiv C H (I)$
$C H_{3} - C \equiv C - C H_{3} (I I)$
$C H_{3} - C H_{2} - C H_{2} - C H_{3} (I I I)$
$C H_{3} - C H = C H_{2} (I V)$

alk.

K M n O_{4}

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B r_{2} / C C l_{4}

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B r_{2} / C H_{3} C O O H

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A m m o n i c a l A g N O_{3}

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Solution

The correct option is D $A m m o n i c a l A g N O_{3}$
Among all given compounds only compound I has acidic hydrogen and Ammonical $A g N O_{3}$ only reacts with acidic hydrogen so it will react with I only and can be used to distinguish between I and rest of all.
All other reagents reacts with all compounds.

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Similar questions

(i) C H_{3} - C \equiv C - C H_{3}

(i i) C H_{3} - C H_{2} - C H_{2} - C H_{3}

(i i i) C H_{3} - C H_{2} - C \equiv C H

(i v) C H_{3} - C H = C H_{2}

1. C H_{3} - C \equiv C - C H_{3}

2. C H_{3} - C H_{2} - C H_{2} - C H_{3}

3. C H_{3} - C H_{2} C \equiv C H

4. C H_{3} - C H = C H_{2}

(i) C H_{3} - C \equiv C - C H_{3}

(i i) C H_{3} - C H_{2} - C H_{2} - C H_{3}

(i i i) C H_{3} - C H_{2} - C \equiv C H

(i v) C H_{3} - C H = C H_{2}

C h_{3} C = C - C H_{3}

C H_{3} C H_{2} - C H_{2} - C H_{3}

C H_{3} C H_{2} C = C H

C H_{3} C H = C H_{2}

(C_{3} H_{4})

B r_{2} / C C l_{4}

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