Which reducing agent is used for the following conversion?
$R C O O H \to R C H_{2} O H$

L i A l H_{4}

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N a B H_{4}

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K_{2} C r_{2} O_{7}

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K M n O_{4}

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Solution

The correct option is B $L i A l H_{4}$
$R C O O H \to R C H_{2} O H$ is reduction reaction of carboxylic acid group to corresponding alcohol. Thus a strong reducing agent is required for the conversion.
$L i A l H_{4}$ is a strong reducing agent while $N a B H_{4}$ is weak reducing agent.
$K_{2} C r_{2} O_{7}$ and $K M n O_{4}$ are oxidising agents.
Thus $L i A l H_{4}$ can bring the $R C O O H \to R C H_{2} O H$ conversion.

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