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Question

Which relations are correct for an aqueous dilute solution of K3PO4 if its degree of dissociation is α?

A
ΔPPo=Molality×18×(1+3α)1000
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B
ΔPPo=πobs×18×(1+3α)RT×1000
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C
ΔPPo=ΔTfobs×18Kf×1000
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D
MwofK3PO4=Mwobs×(1+3α)
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Solution

The correct options are
B ΔPPo=ΔTfobs×18Kf×1000
C ΔPPo=Molality×18×(1+3α)1000
D MwofK3PO4=Mwobs×(1+3α)
ΔPPo=n2n1=n2×Mw1×1000W1×1000=Molality×Mw11000

For electrolyte ΔPPo=Molality×M1000×(1+3α)
(Mw1=18forH2O)

Also,πobs=C×R×T(1+3α)

ΔPPo=πobsRT×181000

ΔTfobs=Kf×molality×(1+3α)

ΔPPo=ΔTfobs×18Kf×100

i=(1+3α)=CalculatedmolecularweightObservedmolecularweight
Therefore, molecular weight of K3PO4=Mobs×(1+3α)

Hence, options A,C and D are correct relations

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