The correct option is B A Section
Total number of students passed in annual exams in a section
= [(No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams)] in that section
∴ Success rate in annual exams in Section A
=[No. of students of Section A passed in annual examsTotal number of students in Section A×100]%
=[(14+64)(28+14+6+64)×100]%
=[78112×100]%
=69.64%.
Similarly, success rate in annual exams in:
Section B [(12+55)(23+12+17+55)×100]% =[67107×100]% =62.62%.
Section C [(8+46)(17+8+9+46)×100]% =[5480×100]% =67.5%.
Section D [(13+76)(27+13+15+76)×100]% =[89131×100]% =67.94%.
Clearly, the success rate in annual examination is maximum for Section A.