Which selection is the correct formula for the nitrite ion?

{N O}_{3}^{-}

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{N O}_{2}^{-}

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N_{3}^{-}

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O {C N}^{-}

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F e {(C N)}_{6}^{3 -}

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Solution

The correct option is B ${N O}_{2}^{-}$
Nitrite ion is N $O_{2}^{(-)}$ ,Nitrate ion is N $O_{3}^{(-)}$ , $N_{3}^{(-)}$ is azide group.

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