Which sequence of reactions shows correct chemical relation between sodium and its compounds?

N a + O_{2} ⟶ N a_{2} O H C l (a q) - ---- \to N a C l c o_{2} - ---- \to N a_{2} C O_{3} Δ - ---- \to N a

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N a o_{2} - ---- \to N a_{2} O H_{2} O - ----- \to N a O H c o_{2} - ---- \to N a_{2} C O_{3} Δ - ---- \to N a

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N a + H_{2} O ⟶ N a O H H C l - ----- \to N a C l c o_{2} - ---- \to N a_{2} C O_{3} Δ - ---- \to N a

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N a + H_{2} O ⟶ N a O H c o_{2} - ---- \to N a_{2} C O_{3} H C l - ----- \to N a C l (m o l t e n) E l e c t r o l y s i s - ------ \to N a

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Solution

The correct option is D $N a + H_{2} O ⟶ N a O H c o_{2} - ---- \to N a_{2} C O_{3} H C l - ----- \to N a C l (m o l t e n) E l e c t r o l y s i s - ------ \to N a$
$2 N a + 2 H_{2} O \to 2 N a O H + H_{2}$
$2 N a O H + C O_{2} \to N a_{2} C O_{3} + H_{2} O$
$2 N a_{2} C O_{3} + 2 H C l \to 2 N a C l + H_{2} O + C O_{2}$
$\begin{matrix} N a C l (m o l t e n) & E l e c t r o l y s i s - ------ \to & N a^{+} & + & C l^{-} ↓ + e & ↓ - e N a & C l \end{matrix}$

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