Which series have highest energy in hydrogen spectrum?

Balmer

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Bracket

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Pfund

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Lyman

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Solution

The correct option is D Lyman
Energy of electron varies with $\frac{1}{n^{2}}$ i.e principal quantum number. For lyman series principal quantum number $(n)$ is 1. Hence, Lyman series have highest energy in hydrogen spectrum.

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Similar questions

Q. The highest energy in Balmer series, in the emission spectra of hydrogen is represented by:

(R_{H} = 109737 {c m}^{- 1})

Q. Calculate the wave number of the highest energy transition in the Balmer series of the hydrogen atom:

[R_{H} = 109678 c m^{- 1}]

Q. The highest energy in Balmer series, in the emission spectra of hydrogen is represented by

(R_{H} = 109737 c m^{- 1})

Q. Assertion :For Balmer series of hydrogen spectrum, the value

n_{1} = 2

and

n_{2} = 3, 4, 5

. Reason: The value of n for a line in Balmer series of hydrogen spectrum having the highest wave length is

4

and

6

The correct relationship between wave numbers of spectral lines, in Balmer series of hydrogen atom having the least and highest wave - lengths, is given by

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Which series have highest energy in hydrogen spectrum?

The correct option is D LymanEnergy of electron varies with 1n2 i.e principal quantum number. For lyman series principal quantum number(n) is 1. Hence, Lyman series have highest energy in hydrogen spectrum.

The correct option is D Lyman
Energy of electron varies with $\frac{1}{n^{2}}$ i.e principal quantum number. For lyman series principal quantum number $(n)$ is 1. Hence, Lyman series have highest energy in hydrogen spectrum.