Question

Which set of products are expected on reductive ozonolysis of the following diolefin?

• A. $C{H}_{3}CHO;C{H}_{3}COCH=C{H}_2$
• B. $C{H}_{3}CH=C\left(C{H}_3\right)CHO;C{H}_{2}O$
• C. $C{H}_{3}CHO;C{H}_{3}COCHO;C{H}_{2}O$
• D. $C{H}_{3}CHO;C{H}_{3}COC{H}_3;C{H}_{2}O$

Answer 1

The correct option is C $C{H}_{3}CHO;C{H}_{3}COCHO;C{H}_{2}O$

Ozonolysis of alkenes involves the addition of an ozone molecule to an alkene, to form an ozonide. Formed ozonide gets cleaved by $Zn-H_{2}O$ to smaller oxidised molecules.
Here, both the double will undergo ozonolysis to form three smaller oxidised molecule.