Which set of rational numbers is arranged in ascending order?

- \frac{5}{14}, - \frac{25}{28}, - \frac{3}{7}, - \frac{1}{2}

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- \frac{25}{28}, \frac{- 5}{14}, \frac{- 3}{7}, - \frac{1}{2}

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- \frac{25}{28}, - \frac{1}{2}, - \frac{3}{7}, - \frac{5}{14}

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- \frac{1}{2}, \frac{- 3}{7}, \frac{- 5}{14}, \frac{- 25}{28}

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Solution

The correct option is C $- \frac{25}{28}, - \frac{1}{2}, - \frac{3}{7}, - \frac{5}{14}$
$- \frac{1}{2} = - \frac{14}{28}$

$- \frac{3}{7} = - \frac{12}{28}$

$- \frac{5}{14} = - \frac{10}{28}$

$∴$ Ascending order $: - \frac{25}{28}, - \frac{1}{2}, - \frac{3}{7}, - \frac{5}{14}$

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Similar questions

Q. Find the mode of the following observations.

(i) 25, 14, 28, 17, 18, 14, 25, 14, 17, 14

(i i) 0, 6, 1, 5, 6, 2, 0, 4, 6, 3, 4, 6, 3, 1

Find the sum:
(i) 2+4+6+...+200
(ii) 3+11+19+...+803
(iii) (-5)+(-8)+(-11)+...+(-230)
(iv) 1+3+5+7+...+199
(v) $7 + 10 \frac{1}{2} + 14 + . . . + 84$
(vi) 34+32+30+...+10
(vii) 25+28+31+...+100
(viii) $18 + 15 \frac{1}{2} + 13 + . . . + (- 49 \frac{1}{2})$

Q. If the value of

\frac{2}{5} \times (- \frac{3}{7}) - (\frac{1}{6} \times \frac{3}{2}) + (\frac{1}{14} \times \frac{2}{5})

\frac{p}{- 28}

, then

p

is equal to?

Simplify:
$(\frac{- 4}{5} \times \frac{15}{8}) + (\frac{- 1}{3} \times \frac{- 9}{7}) - (\frac{2}{1} \times \frac{25}{14})$

Q. (78 - 28) + 25

\div

\times

7 = 100

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Which set of rational numbers is arranged in ascending order?

The correct option is C −2528,−12,−37,−514−12=−1428−37=−1228−514=−1028∴ Ascending order :−2528,−12,−37,−514

The correct option is C $- \frac{25}{28}, - \frac{1}{2}, - \frac{3}{7}, - \frac{5}{14}$
$- \frac{1}{2} = - \frac{14}{28}$

$- \frac{3}{7} = - \frac{12}{28}$

$- \frac{5}{14} = - \frac{10}{28}$

$∴$ Ascending order $: - \frac{25}{28}, - \frac{1}{2}, - \frac{3}{7}, - \frac{5}{14}$