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Quantum Number

Which sets of...

Question

Which sets of quantum no.are consistent with the theory?

n = 2, l = 1, m = 0, s = - \frac{1}{2}

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n = 4, l = 3, m = - 2, s = - \frac{1}{2}

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n = 3, l = 2, m = - 3, s = + \frac{1}{2}

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n = 4, l = 3, m = - 3, s = + \frac{1}{2}

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Solution

The correct options are
A $n = 2, l = 1, m = 0, s = - \frac{1}{2}$
B $n = 4, l = 3, m = - 2, s = - \frac{1}{2}$
D $n = 4, l = 3, m = - 3, s = + \frac{1}{2}$
Values of quantum no.'s
$n = 1, 2, 3, 4.......$
$l = 0$ to $n - 1$
$m = - l$ to $l$ .
$s = - 1 / 2$ and $1 / 2$
So in C, $m = - 3 > l$ , which is not possible.

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Similar questions

n = 4, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{1} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

n = 3, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 1, m_{1} = - 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 2, m = + 1, s = - \frac{1}{2}

n = 3, l = 2, m = - 1, s = + \frac{1}{2}

n = 3, l = 1, m = 0, s = + \frac{1}{2}

n = 5, l = 2, m = + 1, s = - \frac{1}{2}

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

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