The correct option is D CH4
SO2 has 2 bond pairs and 1 lone pair so steric number is 3 and hydrisisation is sp2. Hence it has trigonal planar geometry and bond angle is around 1200.
BeCl2 has 2 bond pairs and 0 lone pair so steric number is 2 and hydrisisation is sp. Hence it has linear geometry and bond angle is 1800.
BF3 has 3 bond pairs and 0 lone pair so steric number is 3 and hydrisisation is sp2. Hence it has trigonal planar geometry and bond angle is 1200.
CH4 has 4 bond pairs and 0 lone pair so steric number is 4 and hydrisisation is sp3. Hence it has tetrahedral geometry and bond angle is 109.5o.
Hence, option d is the correct answer.