Radius of electron in hydrogen atom = a0 n^2
where a0 is 52.9 pm
For ground state n = 1
thus radius of ground state = a0 ... eq 1
And radius of hydrogen like species is given by :
radius of electron in hydrogen like atom = a0 (n^2/z)
where Z is the atomic number of atom.
For Be3+ ion, Z = 4
Radius of electron in nth orbit of Be3+ ion = a0 (n^2/4) .. eq 2
Equating equation 1 and 2 to find the value of n
a0 (n^2/4) = a0
⇒n = 2
Thus 2nd state of the triply ionised beryllium(Be3+ ion) has the same orbit radius as that of ground state of hydrogen atom.