Question

Which statement about the following reaction is true?

• A. In the intermediate the most positive carbon is $s{p}^2$ hybridized, and the transition state leading to A and B are of equal energy
• B. In the intermediate the most positive carbon is $s{p}^3$ hybridized, but it flips rapidly between the two pyramidal forms. As a consequence A and B are produced in equal amounts
• C. In the intermediate the most positive carbon is $s{p}^2$ hybridized, but the less sterically strained product A predominates
• D. In the intermediate the most positive carbon is $s{p}^3$ hybridized, and therefore, the transition states leading to A has lower energy

Answer 1

The correct option is A In the intermediate the most positive carbon is $s{p}^2$ hybridized, and the transition state leading to A and B are of equal energy

In the intermediate, the most positive carbon is $sp2$ hybridized , and the transition state leading to A and B are of equal energy. A and B represent a pair of enantiomers.