Question

Which statement is correct for $(C{H}_3{)}_3$ and $(Si{H}_3{)}_{3}N$?

• A. Both have same shape
• B. $(C{H}_3{)}_{3}N$ is planar while $(Si{H}_3{)}_{3}N$ is pyramidal
• C. $(C{H}_3{)}_{3}N$ is pyramidal while $(Si{H}_3{)}_{3}N$ is planar
• D. Both are pyramidal

Answer 1

The correct option is C $(C{H}_3{)}_{3}N$ is pyramidal while $(Si{H}_3{)}_{3}N$ is planar

$(C{H}_3{)}_{3}N$ has ${sp}_3$ hybridization on nitrogen with pyramidal shape due to p$\pi$-p$\pi$ bonding...whereas in $(Si{H}_3{)}_{3}N$ Si has vacant d orbitals which provides p$\pi$-d$\pi$ bonding and so nitrogen has sp2 hybridization with trigonal planar shape

So Option C is correct