Which statement is false for the balanced equation given below?
$C S_{2} + 3 O_{2} \to 2 S O_{2} + C O_{2}$

One mole of

C S_{2}

will produce one mole of

C O_{2}

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The reaction of

16 g

O_{2}

produces

7.33 g

C O_{2}

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The reaction of one mole of

O_{2}

will produce

\frac{2}{3}

mole of

S O_{2}

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Six molecules of

O_{2}

require three molecules of

C S_{2}

for a complete reaction

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Solution

The correct option is D Six molecules of $O_{2}$ require three molecules of $C S_{2}$ for a complete reaction
For the given reaction,
$C S_{2} + 3 O_{2} \to 2 S O_{2} + C O_{2}$

1 mole of $C S_{2}$ reacts with 3 moles of $O_{2}$ to produce 2 moles of $S O_{2}$ and 1 mole of $C O_{2}$

3 $\times$ 32 g of $O_{2}$ produces 44 g of $C O_{2}$
So, 16 g of $O_{2}$ will produce 7.33 g of $C O_{2}$

3 moles of $O_{2}$ produces 1 mole of $S O_{2}$
So, 1 mole of $O_{2}$ will produce $\frac{2}{3}$ moles of $S O_{2}$

3 molecules of $O_{2}$ require 1 molecule of $C S_{2}$
So, 6 molecule of $O_{2}$ will require 2 molecules of $C S_{2}$

$∴$ option 'd' is incorrect

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