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Equivalent Mass

Which stateme...

Question

Which statement(s) is/are correct about equivalent mass (E) in the given reaction?
$N_{2} + 3 H_{2} ⟶ 2 N H_{3}$

E_{N_{2}} = 4.67

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E_{H_{2}} = 1

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E_{N H_{3}} = 5.67

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E_{N H_{3}} = 2.83

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Solution

The correct options are
A $E_{N_{2}} = 4.67$
B $E_{H_{2}} = 1$
C $E_{N H_{3}} = 5.67$
Reaction:
$N_{2} + 3 H_{2} ⟶ 2 N H_{3}$
0 0 -3 +1
Equivalent weight $= \frac{m o l a r w e i g h t}{n - f a c t o r}$
So,
$E_{N_{2}} = \frac{28}{6} = 4.67$
$E_{H_{2}} = \frac{2}{2} = 1$
$E_{N H_{3}} = \frac{17}{3} = 5.67$

Suggest Corrections

Similar questions

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