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Monosaccharide

0 .and path b...

Question

Which statement (s) is /are correct about the products from (D) by path (a) and path (b)?

Path (a) proceeds via the cleavage of

C - 3

and

C - 4

bond of (D)

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Path (a) proceeds via the cleavage of

C - 4

and

C - 5

bond of (D)

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Path (b) proceeds via the cleavage of

C - 3

and

C - 4

bond of (D)

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Path (b) proceeds via the cleavage of

C - 4

and

C - 5

bond of (D)

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Solution

The correct options are
A Path (a) proceeds via the cleavage of $C - 3$ and $C - 4$ bond of (D)
D Path (b) proceeds via the cleavage of $C - 4$ and $C - 5$ bond of (D)
Path ‘a’ involves the cleavage of `C_3-C_4` bond followed by decarboxylation. However, path ‘b’ proceeds by cleaving the `C_4-C_5` bond.

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x + 2 y - 4 = 0

2 x + 4 y - 12 = 0

A

3 x + 4 y - 12 = 0

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6 x + 8 y - 48 = 0

45^{0}

135^{0}

A \to C \to B .

T_{0}

B = B_{0} t

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