Which statements are correct about $M I C$ (methyl isocyanate, $M e - N = C = O$ ).

M I C

is prepared by the reaction of

{M e N H}_{2}

and

{C O C l}_{2}

(phosgene).

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⎛ ⎜ ⎜ ⎝ M e - N H - O | | C - O H ⎞ ⎟ ⎟ ⎠

Hydrolysis of MIC gives (see diag.) as the intermediate, which gives

{M e N H}_{2}

and

{C O}_{2}

on further hydrolysis.

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M I C

is used to prepare insecticide, carbaryl under the commercial name Sevin.

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(↶ N = C)

bond takes part when l-naphthol is reacted with

M I C

because N is more basic and nucleophilic.

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Solution

The correct options are
A $M I C$ is prepared by the reaction of ${M e N H}_{2}$ and ${C O C l}_{2}$ (phosgene).
B
$M I C$ is used to prepare insecticide, carbaryl under the commercial name Sevin.

C
$⎛ ⎜ ⎜ ⎝ M e - N H - O | | C - O H ⎞ ⎟ ⎟ ⎠$
Hydrolysis of MIC gives (see diag.) as the intermediate, which gives ${M e N H}_{2}$ and ${C O}_{2}$ on further hydrolysis.
D
$(↶ N = C)$ bond takes part when l-naphthol is reacted with $M I C$ because N is more basic and nucleophilic.

$(a, b, c, d)$
Note: In ${C H}_{2} = C = O, R - C \equiv N, R - N = C = O$ ,and $R - N = C = S$ ,
$N A$ reaction occurs.
(b) (diagram)

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