Which step in the following problem is wrong?
$a = b = 1$
$a = b$
step-1: $a^{2} = a b$
step-2: $a^{2} - b^{2} = a b - b^{2}$
step-3: $(a + b) (a - b) = b (a - b)$
step-4: a + b = $\frac{b (a - b)}{a - b}$
$a + b = b$
$1 + 1 = 1$
$2 = 1$

Step-4

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Step-3

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Step-2

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Step-1

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Solution

The correct option is B Step-4
Given that : $a = b = 1$
$⟹ a - b = 0$

In step $4$ , denominator is $a - b$ which is equal to $0$
As denominator being zero is not defined, step- $4$ is wrong.

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Similar questions

A_{2} + B_{2} \to 2 A B

A_{2} \to A + A

A + B_{2} \to A B + B

A + B \to A B

A = [\begin{matrix} 2 & - 1 0 & 1 \end{matrix}]

B = [\begin{matrix} 1 & 0 - 1 & - 1 \end{matrix}],

(A + B)^{2} = A^{2} + A B + B A + B^{2} = A^{2} + 2 A B + B^{2}

A = (\begin{matrix} i & 0 0 & i \end{matrix})

B = (\begin{matrix} 0 & - i - i & 0 \end{matrix})

i = \sqrt{- 1}

(A + B) (A - B)

A^{2} - B^{2}

A B = B A

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