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B
7s
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C
5d
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D
6d
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Solution
The correct option is B7s (n+l) value of 5f=5+3=8. Hence before it the (n+l) value 7 is filled. Also for (n+l) value 7, mass value of n will be filled just before (n+l) value 8, i.e., n=7,l=0 This 7s orbital is filled just before 5f