You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electrochemical Series

Which substan...

Question

Which substance is most easily reduced?

I_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B r_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A t_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $F_{2}$
Fluorine $F_{2}$ is most easily reduced.
Fluorine is most electronegative element and hence, easily accepts an electron to form fluoride ion. This makes fluorine the strongest oxidising agent. It is due to smaller size, low bond enthalpy, high electron affinity and high exothermic hydration energy of the small fluoride ion.

Suggest Corrections

Similar questions

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

F_{2}, C l_{2}, B r_{2}, I_{2}

B r_{2}

N a F, N a C l & N a I

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

Join BYJU'S Learning Program