The correct option is B FC Phagwara & Chennaiyan FC
Number of matches played =Wins + Draws + Losses
Total Points =(4×wins)+(2×draws)
According to statement (I), number of losses of Bangalore City FC =20-(7+4) =9 =Number of losses of FC Chandigarh.
According to statement (II), matches played by FC Pune City =(3×7)=21
According to statement (III), Total matches by FC Pune City =21=5+5+x
So, x =11 and hence draws for FC Phagwara=11
According to the statement (IV), Wins, loss and draw of Kerala Blasters FC are 5, 6 and 7 respectively.
According to the statement (V), let wins and losses by Chennaiyan FC be y. So, the number of draws is (20-2y).
Similarly for Atletico De Kolkata, wins =8 and losses =4.
The number of second lowest losses is that of Atletico De Kolkata which is equal to 4. Hence, y = 4
TeamsMatchesWinsDrawLostPointsAtletico1987446De KolkataChennaiyan FC20412440FC Goa1986544FC Pune City21551130Keral Blasters FC1857634Mumbai City FC1948732Northeast United FC2095646FC Chandigarh1964932Delhi Dynamos FC20112748FC Phagwara18511242Bangalore City FC2074936FC Bihar2175938
Both the teams have a total of 16 (wins and draws combined).