Which temperature is lower $- 7 ° C$ or $- 3 ° C$ .

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Solution

Let's observe the temperature. here both are the negative degree and in the negative integer, the larger numeral is lower than smaller numeral.
Hence, $- 7 ° C$ is lower than $- 3 ° C$ .

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Which temperature is lower? $- 4 ° C o r 3 ° C$

Answer in one word.

Which temperature is lower $5 ° C o r - 5 ° C$

{(b - c)}^{7} + {(c - a)}^{7} + {(a - b)}^{7}

{(a x + \frac{b}{x})}^{14}

14! a^{7} b^{7}

\frac{14!}{7!} a^{7} b^{7}

\frac{14!}{{(7!)}^{2}} a^{7} b^{7}

\frac{14!}{{(7!)}^{3}} a^{7} b^{7}

\frac{a}{| z_{1} - z_{2} |} = \frac{b}{| z_{2} - z_{3} |} = \frac{c}{| z_{3} - z_{1} |} (a, b, c \in R),

then \frac{a^{2}}{z_{1} - z_{2}} + \frac{b^{2}}{z_{2} - z_{3}} + \frac{c^{2}}{z_{3} - z_{1}}

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