Which term in the expansion of {(x√y)1/3+(yx1/3)1/2}21 contains x and y to one and the same power?
Tn=Tr+1=nCrxn−ryr
=21Cr((x√y)13)21−r⎛⎜⎝(yx13)12⎞⎟⎠r
=21Cr(x7−r3y72−r6)yr2xr6=x7−r3−r6y72−r6−r2
⇒x45−2r−r6=y21−r−3r6
Since x and y have same power
42−3r6=−(21−4r)6
=42+21=4r+3r
63=7r
r=9
Term is 10th
(tn=Tr+1)