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Question

Which term in the expansion of {(xy)1/3+(yx1/3)1/2}21 contains x and y to one and the same power?

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Solution

Tn=Tr+1=nCrxnryr

=21Cr((xy)13)21r(yx13)12r

=21Cr(x7r3y72r6)yr2xr6=x7r3r6y72r6r2

x452rr6=y21r3r6

Since x and y have same power

423r6=(214r)6

=42+21=4r+3r

63=7r

r=9

Term is 10th

(tn=Tr+1)


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