Which term of A.P. $92, 88, 84, 80, . . . . .$ is $0$ ?

24

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32

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33

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12

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Solution

The correct option is A $24$
A.P is $92, 88, 84, 80, . . .$
$d = 88 - 92 = - 4 a = 92$
Let 'o' be the $n^{t h}$ term
$a + (n - 1) d = 0 92 - 4 (n - 1) = 0 4 (n - 1) = 92 n = 24$
$0 i s t h e 24^{t h}$ term

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