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Question

Which term of the A.P.3,15,27,39, will be132 more than its 54th term?


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Solution

Determine the term that is 132 terms longer than the54th term.

Given,

A.P.is3,15,27,39,

First term,a=3, n=54, common difference d=15-3=27-15=12

a54th=a+(n1)d=3+(541)12

=3+53×12

=3+636

=639

Let nth term is 132 more than 54th term

132+639=771=an

771=3+(n1)12

76812+1=n

64+1=n

n=65

Hence , the 65th term is 132 more than 54th term.


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