Let nth term of the given AP be 210.
Here, first term,
a = 21
And common difference,
d = 42 – 21 = 21 and
an = 210
∵an=a+(n−1)d
⇒ 210 = 21 + (n - 1)21
⇒ 210 = 21 + 21n - 21
⇒ 210 = 21n
⇒ n = 10
Hence, the 10th term of the AP is 210.