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Question

Question 11
Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?

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Solution

Given A.P. is 3,15,27,39,a=3d=a2a1=153=12a54=a+(541)d=3+(53)(12)=3+636=639132+639=771We have to find the term of this A.P. which is 771.Let nth term be 771.an=a+(n1)d771=3+(n1)12768=(n1)12(n1)=64n=65Therefore, 65th term is 132 more than 54th term.

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