Given A.P. is 3,15,27,39,……a=3d=a2−a1=15−3=12a54=a+(54−1)d=3+(53)(12)=3+636=639132+639=771We have to find the term of this A.P. which is 771.Let nth term be 771.an=a+(n−1)d771=3+(n−1)12768=(n−1)12(n−1)=64n=65Therefore, 65th term is 132 more than 54th term.