Which term of the A.P. 5, 12, 19, 26, ............ is 145

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 21
Here first term $a = 5$ and common difference
$d = 12 - 5 = 7$
Suppose nth term of the A.P. is 145
Now, $T_{n} = a + (n - 1) d$
$∴ 145 = 5 (n - 1) (7)$
$∴ 145 - 5 = 7 (n - 1)$
$∴ 140 = 7 (n - 1)$
$∴ 20 = n - 1 ∴ n = 21$

Suggest Corrections

Similar questions

19, 18 \frac{1}{5}, 17 \frac{2}{5}, . . .

Column I	Column II
(a) How many terms are there in the AP 8, 13, 18, 23,..., 163?	(p) 65
(b) 12th term from the end of the AP 9, 12, 15, 18, ..., 98 is	(q) 25
(c) The sum of the AP 5 + 12 + 19 + 26 + ... + 145 is	(r) 32
(d) The number of terms in the AP (−5) + (−1) + 3 + 7 + ... + 91 is	(s) 1575

Join BYJU'S Learning Program