Question

Which term of the $A.P.92,88,84,80,..$ is $0$?

Answer 1

$T_n=a+(n-1)d$

$a=92$

$d=88-92=84-88=-4$

$0=92+(n-1)(-4)$

$4(n-1)=92$

$n-1=23$

$\therefore n=24$

24th term is the 0