Question

Which term of the $AP5,15,25$ .......will be $130$ more than the $3^{th}$ term .

Answer 1

$6,12,25-----130$

here $d=10$

and $n^{th}$ term is $T_n=a+(n-1)d$

hear given $T_n=130$ & $a=5$

we have to find n

So,

$130=5+(n-1)10$

$125=(n-1)10$

$n-1=\frac{125}{10}$

$n=\frac{125}{10}+1\Rightarrow n=\frac{135}{10}=13.5$

and n con't be 13.5

so, no term will be 130.