Which term of the AP 121, 117, 113 is the first negative term?

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Solution

Given series is $121, 117, 113, . . . .$
The common difference s $- 4$
let the first negative number be $n t h$ Term
$121 - 4 n < 0 121 < 4 n n > 30.25$
The least such number s $31$
The 31st term is $121 - 4 (31) = - 3$

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