Which term of the AP 18, 23, 28, 33, ……. is 98?

15^{t h}

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16^{t h}

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17^{t h}

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18^{t h}

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Solution

The correct option is C $17^{t h}$
Given, series is 18, 23, 33, ........
$∵ a_{n} = a + (n - 1) d$
Here, 1 $^{s t}$ term (a) = 18,
common difference (d) = 23-18 = 5
and a $_{n}$ =98
$∴ 98 = 18 + (n - 1) 5 \Rightarrow 98 - 18 = (n - 1) 5 \Rightarrow \frac{80}{5} = n - 1 \Rightarrow n = 17$

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Which term of the AP 18, 23, 28, 33, ……. is 98?

The correct option is C 17thGiven, series is 18, 23, 33, ........ ∵an=a+(n−1)d Here, 1st term (a) = 18, common difference (d) = 23-18 = 5 and an=98 ∴98=18+(n−1)5⇒98−18=(n−1)5⇒805=n−1⇒n=17

The correct option is C $17^{t h}$
Given, series is 18, 23, 33, ........
$∵ a_{n} = a + (n - 1) d$
Here, 1 $^{s t}$ term (a) = 18,
common difference (d) = 23-18 = 5
and a $_{n}$ =98
$∴ 98 = 18 + (n - 1) 5 \Rightarrow 98 - 18 = (n - 1) 5 \Rightarrow \frac{80}{5} = n - 1 \Rightarrow n = 17$