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Question

Which term of the AP 3, 15, 27, 39, .... will be 132 more than its ​54th term?

A
64th
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B
56th
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C
65th
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D
67th
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Solution

The correct option is C 65th
a=3
d=153=12
Let the required term be the ​nth term.
an=a+(n1)d
a54+132=(32+53×12)+132
=32+636+132=800=an
800=32+(n1)12
768=(n1)12n1=76812=64n=64+1=65
Thus, 65th term is 132 more than 54th term.

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