Which term of the AP : 4, 9, 14,........ , is 89 ?
A
18
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B
14
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C
12
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D
20
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Solution
The correct option is A 18 The sequence is 4, 9, 14, 19, ....89. Given, 'a' = 4, 'd' = 5, last term = 89, 'n' = ? tn=a+(n−1)d⟹89=4+(n−1)5⟹89=4+5n−5⟹89=5n−1⟹5n=90orn=18 89 is the 18th term.