53, 48, 53..........
First term or 'a' = 53
Common difference or 'd' = 48 - 53 = - 5
Let nth term is the first negative term of the given AP.
Now,
nth term in AP = a + (n - 1)*d
= 53 + (n -1)*(- 5)
= 53 - 5n + 5
= 53 + 5 - 5n
= 58 - 5n
Now, we have to find the suitable value of n, so that the value of (58 - 5n) is negative.
Let us take n = 11
nth term = 58 - (5*11)
= 58 - 55
= 3
Which is not negative.
Now, putting n = 12, we get.
nth term = 58 - (5*12)
= 58 - 60
= - 2
This is the first negative term of the series and it is the 12th term of the AP.
So, n =12