Question

Which term of the AP $6,13,20,....$ is $111$?

Answer 1

Let the $n$ th term of the given A.P. will be $111$.

The first term of the given A.P. is $6$ and the common difference is $7$.

Then the $n$ th term will be $6+7(n-1)$.

Then,

$6+7(n-1)=111$

or, $7(n-1)=105$

or, $n=16$.

So $16$ th term of the A.P. is $111$.