Question

Which term of the AP 8, 14, 20, 26,.. will be 72 more than its 41st term?

Answer 1

$a_n=72+a_{41}$

$a_n$ =72+(a+40d) = 72+248 =320

Now, $a_n=a+(n-1)d$

320= 8+(n-1)$\times$ 6

8+6n-6=320

6n= 320-2

6n = 318

n = 53

So, 53rd term of this A.P. will be 72 more than its 41st term.